x^2+0.0415x-0.06225=0

Solution for x^2+0.0415x-0.06225=0 equation:

x^2+0.0415x-0.06225=0

a = 1; b = 0.0415; c = -0.06225;
Δ = b2-4ac
Δ = 0.04152-4·1·(-0.06225)
Δ = 0.25072225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0415)-\sqrt{0.25072225}}{2*1}=\frac{-0.0415-\sqrt{0.25072225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0415)+\sqrt{0.25072225}}{2*1}=\frac{-0.0415+\sqrt{0.25072225}}{2}
$